Question

Jen and her partner were assigned the Zn/Zn cathode/anode pair which they used to construct their electrolytic cell. They decided to keep the concentration of the corresponding Zn2+ solution constant at 1 M. If Jen ran her cell for 22.8 mins, what current (mA) did she use in order to transfer 9 x 10^-4 moles of electrons?

Answer 1

63.2 mA

Step-by-step explanation:

We all know that:

Current
`I = (Q)/(t)`

which can be further expressed as:

`I = (ne)/(t)`

where;

n = number of electrons

e = charge on electrons

t = time (second)

Then; by replacing the values in the question, we have:

`((9*10^(-4))*6*10^(23)*1.6*10^(-19))/(22.8*60)`

`= 0.06316 A \\ \\ \mathbf{I= 63.2 \ mA}`