Question

F(x)=-x^2-4x+12
find the minimum/maximum value

Answer 1

Maximum Value / Vertex : (-2,16)

Explanation:

Since the value of a is negative, we will solve for the maximum.

Finding the x-value of the vertex of the parabola is x=-b/2a:

x=-(-4)/2(-1)

x=4/-2

x=-2

Now if we plug x=-2 into the function, we'll get our y-value for the vertex:

f(-2)=-(-2)^2-4(-2)+12

f(-2)=-(4)+8+12

f(-2)=-4+20

f(-2)=16

So the vertex of our parabola is (-2,16) which is our maximum value