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Which equation describes a line parallel
to y= 4x+ 5 through point (-2, 1)?

User Rhian
by
9.1k points

1 Answer

12 votes

Hi there!

For a line to be PARALLEL, it must contain the same slope.

The given line has a slope of 4, so we can use the point-slope formula to solve:


\large\boxed{y - y_1 = m(x - x_1)}

y1 = y-coordinate of given point

x1 = x-coordinate of given point

m = slope

Plug in the values:


y - 1 = 4(x - (-2))\\\\y - 1 = 4(x + 2)

Simplify:


y - 1 = 4x + 8\\\\\boxed{y = 4x + 9}

User MAHDTech
by
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