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Question below: (thanks!)

Question below: (thanks!)-example-1
User JanLauGe
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1 Answer

4 votes

Answer:

Frequency of SS dominant individuals is
0.57

Step-by-step explanation:

The total population of rabbit is 650

Out of 650 rabbit, nearly 39 have recessive allele "s".

Hence, frequency of recessive genotype =
(39)/(650) = 0.06

Frequency of recessive allele =
√(0.06)


q = √(0.06) = 0.245

Frequency of dominant trait allele "S"
p = 1-q = 1-0.245 = 0.755

Frequency of SS dominant individuals is
p^(2) = 0.755^2 = 0.57

User Jason Roner
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