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Calculate the Standard Enthalpy of the reaction below: NH3(g) + HCl (g) → NH4Cl(s) Using the following Enthalpy of Reactions: 2HCl(g) → H2(g) + Cl2(g) AH = +184.6 kJ 2H2(g) + 12 N2(g) + 2 Cl2(g) NH4Cl(s)
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Calculate the Standard Enthalpy of the reaction below:

NH3(g) + HCl (g) → NH4Cl(s)
Using the following Enthalpy of Reactions:
2HCl(g) → H2(g) + Cl2(g)
AH = +184.6 kJ
2H2(g) + 12 N2(g) + 2 Cl2(g) NH4Cl(s) AH = -314.4 kJ
N2(g) + 3 H2(g) → 2 NH3(g)
AH = +184.6 kJ​

User Chubbsondubs
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Answer:

(we use hess's law) it is so simple but the second reaction is not correct please right it

User Chen Ni
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