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Please help!!! ABCD is a square with diagonals intersecting at E. What is the length of BE

Please help!!! ABCD is a square with diagonals intersecting at E. What is the length-example-1
User Gyzerok
by
7.9k points

1 Answer

1 vote

Answer:


BE = 4\sqrt2

Explanation:

Given

The attached square

Required

Find BE

First, we calculate BD (the diagonal) using Pythagoras theorem.


BD^2 = BA^2 + AD^2

Since the shape is a square, then


BA = AD = 8

So:


BD^2 = 8^2 + 8^2


BD^2 = 2(8^2)

Take square roots


BD = \sqrt{2(8^2)


BD = √(2) * 8


BD = 8√(2)

BE is half BD.

So:


BE = (1)/(2) * BD


BE = (1)/(2) * 8\sqrt2


BE = 4\sqrt2

User Bart Van Loon
by
8.4k points

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