Answer:
2.3 x 10-13 F
Step-by-step explanation:
From the question,
Applying
C = e₁e₂A/d..................... Equation 1
Where C = Capacitance of the capacitor, d = distance of seperation, A = cross sectional area of the capacitor, e₁ = permitivity of free space, e₂ = relative permitivity of vacuum.
But,
Area of a circle (A) is given as
A = πr²................... Equation 2
Where r = radius of the capacitor.
Substitute equation 2 into equation 1
C = e₁e₂πr²/d............... Equation 3
Given: r = 2.5 mm = 0.0025 m, d = 0.75 mm = 0.00075 m
Constant; e₁ = 8.85×10⁻¹² F/m, e₂ = 1 F/m, π = 3.14.
Substitute these values into equation 3
C = [(8.85×10⁻¹²)(1)( 0.0025²)(3.14)]/(0.00075)
C = 0.23×10⁻¹²
C = 2.3×10⁻¹³ F