Question

How many grams of water can be heated from 15.0°C to 75°C using 12,500 Joules?

Answer 1

m = 49.8 g

Step-by-step explanation:

Hello there!

In this case, for this calorimetry processes we can define the involved heat in terms of mass, specific heat and temperature as shown below:

`Q=mC\Delta T`

Thus, given the heat, final and initial temperature and specific heat of water (4.184), the mass of water can be computed as shown below:

`m=(Q)/(C\Delta T)\\\\m=(12500J)/(4.184(J)/(g\°C)(75\°C-15.0\°C)) \\\\m=49.8g`

Best regards!