Question

A 16 gram sample of O2(g) fills a container at STP.
What volume is the container?

Answer 1

V = 11.2 L

Step-by-step explanation:

Hello there!

In this case, according to the ideal gas equation:

`PV=nRT`

It is possible to compute the volume as shown below:

`V=(nRT)/(P)`

Whereas the moles are computed are computed given the mass and molar mass of oxygen:

`n=16g*(1mol)/(32g) =0.5mol`

Now, since the STP stands for a temperature of 273.15 K and a pressure of 1 atm, the resulting volume is:

`V=(0.5mol*0.08206(atm*L)/(mol*K)*273.15K)/(1atm)\\\\V=11.2L`

Best regards!