135k views
3 votes
What are my zeros (x^2 - 8x + 1)?

User Nayakam
by
8.4k points

1 Answer

4 votes

Answer:

x= 7.87298334621 x=.12701665379

Explanation:

This is in standard form so we have to factor this into

x^2-8x + 16 + 1 = 16

(x-4)^2 = 15

(x-4) =
√(15\\)

x-4= ± 3.87298334621

x-4 = 3.87298334621 x-4= -3.87298334621

x= 7.87298334621 x=.12701665379

User Landings
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories