Question

What is the equation for the hyperbola shown?

X
V2
= 1
602
112
72
-
x2
112
1
602
72
x2
=
1
602
112
72
112
x2
602
1

Answer 1

`(x^(2) )/(3600) - (y^(2) )/(121) = 1`

Explanation:

Since the hyperbola opens left and right with a center at the origin, then

`(x^(2) )/(^(2) ) - (y^(2) )/(b^(2) ) = 1`

In the graph a = 60 and b = 11

So

`(x^(2) )/(60^(2) ) - (y^(2) )/(11^(2) ) = 1`.

`(x^(2) )/(3600) - (y^(2) )/(121) = 1`