Question

Please help..
Solve for the area of the figure below and show work.

Answer 1

Answer and Step-by-step explanation:

1. We can see that this kite-shape has 4 triangles in it.

The area of a triangle is as follows:

`A = (bh)/(2)`

Where:

b = Base (length)

h = Height

Top Right Triangle Area:

b = 9

h = 3

A =
`(3 * 9)/(2)`

A =
`(27)/(2)`

Bottom Right Triangle Area:

b = 9

h = 3

A =
`(3 * 9)/(2)`

A =
`(27)/(2)`

Top Left Triangle Area:

b = 4

h = 3

`A = (4*3)/(2)`

A =
`(12)/(2)`

A = 6

Bottom Left Triangle Area:

b = 4

h = 3

`A = (4*3)/(2)`

A =
`(12)/(2)`

A = 6

Now, we add all the areas together to get the area of the kite figure.

A =
`(27)/(2)` +

A = 27 + 12

A = 39

The area of the kite figure is 39
`m^(2)`.

2. We have to find the area of the trapezoid.

(I'm not sure if the 9 is for the entire bottom side length)

• If the bottom side length is 9, then we would use the formula:

A =
`(a + b)/(2) h`

to find the area of the entire trapezoid.

A =
`(2.4 + 9)/(9)` × 8.2

A ≈ 46.74
`mi^(2)`

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