151k views
1 vote
The length of a rectangle is 1 ft less than twice its

width. If the area of the rectangle is 78 ft^2 ,what
are the dimensions of the rectangle?

User Roxerio
by
8.8k points

1 Answer

6 votes

Answer:

Width: 13/2 ft.

Length: 12 ft.

Explanation:

Let's assume the width is x

This means that the length is 2x-1, because it it one less than double the width.

The formula for the area of a rectangle is length*width, so

(2x-1)*x=78

Now let's solve for x

2x^2-x=78

2x^2-x-78=0

Use the quadratic formula

x=13/2 and x=-6

x cannot be negative, so we can rule out x=-6 and are left with x=13/2.

Substituting x back into our original assumptions, we now know that

The width is x=13/2 and

The length is 2x-1=2(13/2)-1=12

Final answer: The width is 13/2 ft. and the length is 12 ft.

User Alexey Stepanov
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories