Answer:
The correct option is;
The fourth option
Please the attached drawing created with MS Visio
Explanation:
From the given figure, we have;
The orientation of ΔSTU is equal to the orientation of ΔS'T'U'
When the plane of reflection is assumed to be the y-axis, we have;
For a reflection about the y-axis, we have;
The coordinate of the preimage = (x, y)
The coordinate of the image after the reflection = (-x, y)
When the image (-x, y) is reflected again across the y-axis, and becomes the image, we have;
The coordinate of the preimage = (-x, y)
The coordinate of the image after the reflection = (x, y)
Therefore, a reflection twice across the same y-axis would result in an image having the same orientation as the preimage
Given that a y-axis is parallel to another y-axis, we have;
A reflection twice across two parallel axis would result in an image having the same orientation as the preimage
The correct option is the 4th option
Please see attached drawing created with MS Visio