Answer:
The kinetic energy at ground will be "238.2 J".
Step-by-step explanation:
The given values are:
mass,
m = 3 kg
Initial height,
h = 3 m
Initial velocity,
v = 10 m/s
By using the conservation of energy at points A and B,
⇒
![E_A=E_B](https://img.qammunity.org/2022/formulas/physics/college/q8plttovh58hfy3pkqknz5lzakgo3pv9kr.png)
⇒
![mgh+(1)/(2)mv^2=k_B](https://img.qammunity.org/2022/formulas/physics/college/mqsezq9hkpl0hur130qf8pto4lyqc5zle9.png)
On substituting the values, we get
⇒
![3* 9.8* 3+(1)/(2)* 3* (10)^2=k_B](https://img.qammunity.org/2022/formulas/physics/college/65j2jag9jxu2czcutt59ixr6tq6ppawcye.png)
⇒
![88.2+0.5* 3* 100=k_B](https://img.qammunity.org/2022/formulas/physics/college/xsq1q5n3753g3i4imskurwsamr3h1hdnlr.png)
⇒
![88.2+150=k_B](https://img.qammunity.org/2022/formulas/physics/college/9vpxa9qcdiueukqa0ryzxhfg55n559mnqq.png)
⇒
![238.2 =k_B](https://img.qammunity.org/2022/formulas/physics/college/9uoi39cfdtp60lznp36ti7hbsscg1xw9ql.png)