Question

help asap show work | a gas with a volume of 13L at a pressure of 197 kPA is allowed to expand to a volume of 23L. what is the pressure of the container if the temperature remains constant

Answer 1

111 kPa

Step-by-step explanation:

The new pressure can be found by using the formula for Boyle's law which is

`P_1V_1 = P_2V_2`

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the new pressure

`P_2 = (P_1V_1)/(V_2) \\`

We have

`P_2 = (13 * 197000)/(23) = (2561000)/(23) \\ = 111347.826...`

We have the final answer as

111 kPa

Hope this helps you