Answer:
The calculated value Z = 1.39 <1.96 at 0.05 level of significance
The null hypothesis is accepted
Explanation:
Step(i):-
Given that the mean of the Population = 43
Given that the mean of the sample = 47
Given that the standard deviation of the Population = 25
Given that the sample size 'n' = 76
Step(ii):-
Null hypothesis:H₀: μ = 43
Alternative Hypothesis: H₁: μ ≠ 43
Test statistic
![Z = (x^(-)-mean )/((S.D)/(√(n) ) )](https://img.qammunity.org/2022/formulas/mathematics/college/q9tndh0ftqcglbyxb90z0rwpvwk4k9xa66.png)
![Z = (47-43 )/((25)/(√(76) ) )](https://img.qammunity.org/2022/formulas/mathematics/college/n46qd4m64vpzyt76o6ald5wgkpxqwxk8ic.png)
Z = 1.39
Level of significance = 0.05
The critical value = 1.96
Final answer:-
The calculated value Z = 1.39 <1.96 at 0.05 level of significance
The null hypothesis is accepted