Answer:
(4/3, -3, 3/2)
Explanation:
f(x)=6x^3+x^2-39x+36
0-6x^3-x^2+39x-36=0
-6x^3-18x^2+17x^2+51x-12x-36=0
-6x^2(x+3)+17(x+3)-12(x+3)=0
-(x=3)(6x^2-17x+12)=0
-(x+3)(6x^2-8x-9x+12)=0
-(x+3)(2x(3x-4)-3(3x-4))=0
-(x+3)(3x-4)(2-3)=0
(x=3)(3x-4)(2x-3)=0
x=-3 x=4/3 x=3/2