Question

The area behind the free throw line on a basketball court is a semicircle with a 6 foot radius. What is the area of the semicircle?

Answer 1

Answer:56.52

let me know if this is wrong

Explanation:

A=πr^2 divided by 2

(3.14)(6)^2

(3.14)(36)=113.04

113.04÷2=56.52