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How many milliliters of 3.0 M H2SO4 are needed to make 450 mL of 0.10 M H2SO4?

2 Answers

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Final answer:

To prepare 450 mL of a 0.10 M H2SO4 solution from a 3.0 M H2SO4 stock solution, 15 milliliters of the stock solution are needed using the dilution equation M1V1 = M2V2.

Step-by-step explanation:

To determine how many milliliters of a 3.0 M H2SO4 are needed to make 450 mL of a 0.10 M H2SO4 solution, we use the dilution equation M1 V1 = M2 V2 where M1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, M2 is the concentration of the diluted solution, and V2 is the volume of the diluted solution.

Step-by-Step Calculation:

  1. Write down the known values: M1 = 3.0 M, M2 = 0.10 M, and V2 = 450 mL.
  2. Insert the known values into the equation: (3.0 M)(V1) = (0.10 M)(450 mL).
  3. Solve for V1: V1 = (0.10 M * 450 mL) / 3.0 M.
  4. Calculate the volume of the stock solution: V1 = 15 mL.

Thus, you would need 15 milliliters of the 3.0 M H2SO4 to make 450 mL of a 0.10 M H2SO4 solution.

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