Question

Pleaseeee need help with this asappp

Answer 1

Here , we are given with a circle on cartesian plane , and we need to find the equation of the circle , We are also given that it's centre is at (5,-6) { From graph } and it's radius is 3 units . Now , as we know, the standard equation of a circle is
`{\bf (x-h)^(2)+(y-k)^(2)=r^(2)}` where (h,k) is the centre of the circle and radius is r . Now , our equation will be ;

`{:\implies \quad \sf (x-5)^(2)+\{y-(-6)\}^(2)=3^(2)}`

`{:\implies \quad \bf \therefore \quad \underline{\underline{(x-5)^(2)+(y+6)^(2)=9}}}`

This is the required equation of Circle

Or if you want to proceed it further , then you will get x² + y² - 10x + 12y + 50 = 0