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5 votes
5 votes
What is the force of repulsion between two points positive charges 5 and 8 separated at a distance of 0.02m apart

User Chris Vig
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1 Answer

24 votes
24 votes

Step-by-step explanation:

F =(frac{1}{4{pi}{varepsilon}_o}) x (frac {q_1q_2}{r^2})

F =(frac {5 {times} 10 {times} 8 {times} 10}{0.002 {times} 0.002}) x 9 x 10

F = 900N

User Abhyudaya Sharma
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