Question

Help please I don't know how to do this and it is due soon!!
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Answer 1

It's isosceles

• A(-3,1)
• B(1,-2)
• C(4,2)

`\\ \rm\hookrightarrow AB=√((-2-1)^2+(1+3)^2)=√(9+16)=√(25)=5`

`\\ \rm\hookrightarrow BC=√((2+2)^2+(4-1)^2)=√(16+9)=5`

`\\ \rm\hookrightarrow AC=√((4+3)^2+(2-1)^2)=√(50)`

• AB=BC

Its isosceles

Answer 2

• its an isosceles triangle

• not a right angle triangle.

part A:

`\sf AB^2 = (-2-1)^2 + (1+3)^2`

`\sf AB^2 =25`

`\sf AB =5`

`\sf AC^2 = (2-1)^2 + (4+3)^2`

`\sf AC^2 = 50`

`\sf AC = √(50)`

`\sf AC = 5√(2)`

`\sf BC^2 = (2--2)^2 + (4-1)^2`

`\sf BC^2 = 25`

`\sf BC = 5`

use the formula:

short side² + short side² = long side²

( 5√2 )² + 5² = ( 5√2 )²

75 = 50