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What is the force of repulsion between two points positive charges 5 and 8 separated at a distance of 0.02m apart
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What is the force of repulsion between two points positive charges 5 and 8 separated at a distance of 0.02m apart

User Arton Dorneles
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1 Answer

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Step-by-step explanation:

F =(frac{1}{4{pi}{varepsilon}_o}) x (frac {q_1q_2}{r^2})

F =(frac {5 {times} 10 {times} 8 {times} 10}{0.002 {times} 0.002}) x 9 x 10

F = 900N

User Daniel Dolz
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4.8k points
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