1 Answer

Jon Ekiz · Answer 1 · 2023-01-07T00:15:54+0000

Answer:

$\sf c = -4$ and
$\sf b = -6$

Step-by-step explanation:

using the formula:
$\sf x = ( -b \pm √(b^2 - 4ac))/(2a)$

Here the a = 1

using the equation:

$3 \pm√(13)= ( -b \pm √(b^2 - 4(1)c))/(2(1))$

$6 \pm2√(13)= -b \pm √(b^2 - 4(1)c)}$

matching the coefficients: b = - 6

find c:

$6 \pm2√(13)= -(-6) \pm √((-6)^2 - 4(1)c)}$

$6 \pm2√(13)= 6 \pm √(36 - 4c)}$

$\sf 6 \pm√(52)= 6 \pm √(36 - 4c)}$

$\sf 36-4c = 52$

$\sf -4c = 52-36$

$\sf -4x = 16$

$\sf c = -4$

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