Question

A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel during 30 seconds of rotation? ​ ​

Answer 1

the distance in meters traveled by a point outside the rim is 157.1 m

Step-by-step explanation:

Given;

radius of the disk, r = 50 cm = 0.5 m

angular speed of the disk, ω = 100 rpm

time of motion, t = 30 s

The distance in meters traveled by a point outside the rim is calculated as follows;

`\theta = \omega t\\\\\theta = (100 (rev)/(\min) * (2\pi \ rad)/(1 \ rev) * (1\min)/(60 s) ) * (30 s)\\\\\theta = 100 \pi \ rad\\\\d = \theta r\\\\d = 100\pi \ * \ 0.5m\\\\d = 50 \pi \ m = 157.1 \ m`

Therefore, the distance in meters traveled by a point outside the rim is 157.1 m