Question

A negative charge of -2.0 x 10-4 C and a positive charge of 6.5 x 10-5C are separated by 0.25 m. What is the

force between the two charges?
A.-18.72N
B.-13N
C.-468N
D.-1872N
E.-0.187N

Answer 1

F = - 1872 N

Explanation:

Given that,

Charge 1,
`q_1=-2* 10^(-4)\ C`

Charge 2,
`q_2=6.5* 10^(-5)\ C`

The distance between charges, r = 0.25 m

We need to find the force between the two charges. The formula for force between two charges is given by :

`F=(kq_1q_2)/(r^2)\\\\F=(9* 10^9* -2* 10^(-4)* 6.5* 10^(-5))/((0.25)^2)\\\\F=-1872\ N`

So, the force between the charges is equal to 1872 N.