Question

`x {}^(2) - 2ax + a {}^(2) - b = 0`
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Answer 1

The answer is the last line.

Explanation:

Use the quadratic formula

a = 1

b = -a

c = a^2 - b

x = -b +/- sqrt(b^2 - 4ac)

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2a

x = a +/- sqrt(a^2 - 4(1)*(a^2 - b)

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2

x = a +/- sqrt(a^2 - 4a^ + 4b)

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2

x = a +/- sqrt(4b - 3a^2)

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2