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What volume would 75.0g of oxygen gas occupy
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What volume would 75.0g of oxygen gas occupy

User Natoya
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Answer:

Explanation: It is already known that 1 mole of the gas( or 32g of O2) is equivalent to 22.4 Litres of the oxygen gas. So, 8g is equivalent to = (22.4/32) × 8 = 5.6 L of the gas.

User JamesE
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