A sample of oxygen at 40.°C occupies 820. mL. If this sample later occupies 1250 mL at 60.°C and 1.40 atm, what was its original pressure?

asked Dec 14, 2023 108k views

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A sample of oxygen at 40.°C occupies 820. mL. If this sample later occupies 1250 mL at 60.°C

and 1.40 atm, what was its original pressure?

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$\tt (P_1V_1)/(T_1)=(P_2V_2)/(T_2)$

T₁=40+273=313

T₂=60+273=333

P₁.820/313 = 1.4.1250/333

P₁=2.006 atm

Kiskae answered Dec 19, 2023

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