Question

A circular hot spring has a diameter of 106 meters. Over time, the diameter of the spring decreases by 2 meters. By how many square meters does the area of the hot spring decrease? Use 3.14 for

Answer 1

The area decreased by 329.7 square meters.

Explanation:

For a circle of diameter D, the area is:

A = pi*(D/2)^2

with pi = 3.14

In this case, we start with a circle of D = 106m

Then the initial area is:

A = 3.14*(106m/2)^2 = 8,820.26 m^2

After, the diameter is decreased by two meters, then the new diameter is:

D' = 106m - 2m = 104m

And the new area will be:

A' = 3.14*(104m/2)^2 = 8,490.56 m^2

The change in the area is A - A' = 8,820.26 m^2 - 8,490.56 m^2 = 329.7m^2

The area decreased by 329.7 square meters.