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A commercial jet liner takes off with an average acceleration of 3 g. How long does it take to reach the end of its runway which is 1524 meters away?

User MapTiler
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Answer:

The time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.

Step-by-step explanation:

Given;

average acceleration of the commercial Jet liner, a = 3g = 3 x 9.8 m/s² = 29.4 m/s²

distance traveled by the commercial Jet liner, s = 1542 m

The time taken for the commercial Jet liner to reach the end of its runway is calculated as follows;

s = ut + ¹/₂at²

where;

u is the initial velocity of the commercial Jet liner = 0

s = 0 + ¹/₂at²

s = ¹/₂at²

2s = at²


t = \sqrt{(2s)/(a) } \\\\t = \sqrt{(2 * 1524)/(29.4) } \\\\t = 10.18 \ s

Therefore, the time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.

User David Groomes
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