Question

\dfrac12(10x + 20y +10z) = 2 1 ​ (10x+20y+10z)=start fraction, 1, divided by, 2, end fraction, left parenthesis, 10, x, plus, 20, y, plus, 10, z, right parenthesis, equals

Answer 1

5x + 10y + 5z

Explanation:

Given the expression

`(1)/(2)(10x+20y+10z)\\`

Expand the parenthesis using the distributive law;

`(1)/(2)(10x)+ (1)/(2)(20y)+(1)/(2)(10z)\\= (10x)/(2) + (20y)/(2) + (10z)/(2)\\= 5x + 10y + 5z`

Hence the required solution is 5x + 10y + 5z