Question

3.2.5
Find a so that the point (-1,4) is on the graph of f(x) = ax^2+1

Answer 1

9514 1404 393

Answer:

a = 3

Explanation:

Evaluating the given function at the point, we have ...

f(-1) = a(-1)^2 +1 = 4

a +1 = 4

a = 3

The value of 'a' is 3.