Question

The equilibrium constant for the reaction shown below is Kc=0.0091. If the equilibrium concentrations of A and B are 0.031 M and 0.0823 M, respectively, what is the equilibrium concentration of C?

Answer 1

`[C]=0.0221M`

Step-by-step explanation:

Hello there!

In this case, according to the given chemical reaction at equilibrium:

`3A\rightleftharpoons 3B+2C`

It is possible for us to set up the equilibrium expression as shown below:

`Kc=([B]^3[C]^2)/([A]^3)`

Whereas Kc, [A] and [B] are known as 0.0091, 0.031M and 0.0823M and it is required to calculate [C]; thus, we solve for it as follows:

`[C]^2=([A]^3Kc)/(B]^3)`

`[C]=\sqrt{((0.031)^3*0.0091)/((0.0823)^3)}`

`[C]=0.0221M`

Best regards!