Given Equation:-
![\sf25 - 12 / [(8 - 5) * 1]](https://img.qammunity.org/2023/formulas/mathematics/middle-school/x4krwcvkm8xarigq9ajh7zm7afo5t9zgro.png)

Step-by-step explanation:-

![\dashrightarrow \sf25 - 12 / [(8 - 5) * 1]](https://img.qammunity.org/2023/formulas/mathematics/middle-school/6v2trz78klhk4r6uupuq7fmt07vrw6szfp.png)
first write the equation so that you'll emit minor mistakes of writing wrong digits.

![\dashrightarrow \sf25 - 12 / [(3) * 1]](https://img.qammunity.org/2023/formulas/mathematics/middle-school/4rr40ew0ghmin32a796lmk4b88cyvmwuhy.png)
subtract 8 and 5 , which will give us result as 3

![\dashrightarrow \sf25 - 12 / [3 * 1]](https://img.qammunity.org/2023/formulas/mathematics/middle-school/xmdhvpd8y7g5av1lwlgokohbe2qsro2rp4.png)
open the brakets that contains 3.

![\dashrightarrow \sf25 - 12 / [3]](https://img.qammunity.org/2023/formulas/mathematics/middle-school/ruacz06e065f3fkn2r6ttzdo4my3p5qhag.png)
multiply 3 with 1 which will result 3.


open the brakets of 3.


to make it easy to understand I have converted it into fraction form.


simplify 12 which is contained in numerator.


as we can see after converting into fraction 3 is common both in numerator and denominator. So cancel ir.


we no longer need the fraction as 3 is canceled.


multiply 2 with 2 which will result 4.


finally after subtracting 25 and 4 , we got our answer as 21.

Rule applied:-
B : bracket
O : on/off
D: divide
M : multiply
A : add
S : subtract