Question

A man is jogging to work. From his house he runs 752 meters west, turns a corner and runs 587 meters south before arriving at work. What is the mans total distance covered AND net displacement (length of displacement and angle)?

Answer 1

`d_t=1339m`

`d_r=953.98`

`x=37.975 \textdegree`

Step-by-step explanation:

From the question we are told that

1st distance
`d_1=752 m`

2nd distance
`d_2=587 m`

Generally the total distance
`d_t`covered by the man is mathematically given as

`d_t =1st\ distance +2nd\ distance`

`d_t=752+587\\d_t=1339m`

Generally the resultant distance traveled is mathematically given as

`d_r^2=d_1^2+d_2^2`

`d_r=√(752^2+587^2)`

`d_r=953.98`

Generally the angle using sine rule traveled is mathematically given as

let angle =x

`(sin90)/(d_r) =(sinx)/(587)`

`sinx=(sin90*587)/(953.98)`

`x=37.975 \textdegree`