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A 10.0kg rock is dropped and hits the ground below at a speed of 60 m/s . Calculate the gravitational potential energy of the rock before it was dropped

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Answer:

Solution:

Mass of body, m= 10kg

velocity, v= 60m/s

Now,kinetic energy on earth= potential energy at a that point [energy conservation]

so, kinetic energy= 1/2*m* v^2

= 1/2* 60(60)^2

= 30* 60*60

= 108000 joules

User Sushil Kandola
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