Question

Zinc metal reacts with aqueous copper(II) chloride, as shown in this equation. If 3.03 x 1021 atoms of zinc react, how many grams of Cu will form? Show the sequence of conversions necessary, then calculate the numerical answer. Zn (s) + CuCl2 (aq) ---> ZnCl2 (aq) + Cu (s)

Answer 1

0.320 g Cu.

Step-by-step explanation:

Hello there!

In this case, case, according to the presented chemical reaction, it is possible to determine that the mole ratio of zinc to copper is 1:1 and therefore, we will have the same amount of atoms for the both of them. Moreover, since one mole of copper contains 6.022x10²³ atoms of this element, with a mass of 63.546 g (molar mass); it is possible for us to write up the following mathematical setup in order to calculate the produced grams of copper:

`3.03x10^(21)atoms Zn*(1atom Cu)/(1atom Zn)*(1molCu)/(6.022x10^(23)atoms Cu)*(63.546gCu)/(1molCu) \\`

Thus, the numerical result turns out to be:

0.320 g Cu

Best regards!