Explanation:
The system of linear equations are , (i) y = 2x and (ii) y = x + 1 . We will find some coordinates and then we will plot its graph. The point where both Graphs will meet will be the solution of the graph .
• Finding coordinates of Equⁿ (i) :-
Step 1 : Put x = 0 :-

Step 2: Put x = 1 :-


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• Finding coordinates of equⁿ (ii) :-
Step 1 : Put x = 0 :-

Step 2: Put x = 1 :-


Now plot these points on the graph Taking appropriate scale . Refer to the attachment in graph . From graph the Solution is (1,2) .