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Camille buys a cake for $\$24.99$ . She also buys $12$ brownies. Each brownie costs the same amount. She spends $\$39.99$ on the cake and the brownies.

Camille finds the cost of each brownie by calculating $(39.99\ -\ 24.99)\ \div\ 12$ . Tanya finds the cost of each brownie by solving the equation $39.99\ +\ 12b\ =\ 24.99$ , where $b$ is the cost of each brownie.

Which approach uses the sequence of operations necessary to find the cost of each brownie: Camille’s, Tanya’s, both, or neither? Explain why.

Respond in the space provided.

1 Answer

3 votes

Answer:

Camille's approach

Explanation:

Each brownie costs $1.25. Tanya's equation is wrong because the end result is the cost of the cake and in order to get that you would need to subtract instead of adding.

User Jose Mhlanga
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