Question

What is an equation of the line that passes through the points (5,-3) and
(-3, -3)?

Answer 1

• (5,-3)
• (-3,-3)

Slope:-

`\\ \rm\hookrightarrow m=(-3+3)/(-3-5)=0`

Equation of line in point slope form

`\\ \rm\hookrightarrow y+3=0(x-5)`

`\\ \rm\hookrightarrow y+3=0`

`\\ \rm\hookrightarrow y=-3`

Answer 2

y=-3

Explanation:

First, you want the slope.

The slope is

`(-3-(-3))/(-3 - 5) = (0)/(-8)\\`

0/-8 = 0, so the line is horizontal.

the y-intercept must be -3 because it never changes.

So the equation must be

y=-3