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There is a new treatment to help smokers stop smoking in an experiment, 80% of 300 smokers quit after 10 days of treatment which of the following is the 95% confidence interval?

(0.7547, 0.8453)
(8096, 08904)
(08048 08952)
(0.749,0 851)

User Nikita Zernov
by
2.7k points

2 Answers

6 votes
6 votes

Answer:

(0.755, 0.845)

Explanation:

I got it right, on the test so trust me!

User Auxdx
by
2.9k points
10 votes
10 votes

The 95% confidence interval for the proportion of smokers who quit after 10 days of treatment is (0.749, 0.851).

Let's calculate the 95% confidence interval for the proportion of smokers who quit after 10 days of treatment.

Step 1: Calculate the sample proportion

The sample proportion is the proportion of smokers in the sample who quit after 10 days of treatment. In this case, the sample proportion is:

p = 80/300 = 0.8

Step 2: Calculate the standard error

The standard error is a measure of the variability of the sample proportion. It is calculated as follows:

SE = sqrt(p(1-p)/n)

where:

p is the sample proportion

n is the sample size

In this case, the standard error is:

SE = sqrt(0.8(1-0.8)/300) = 0.026

Step 3: Calculate the margin of error

The margin of error is the amount by which we can be confident that the true proportion of smokers who quit is within our confidence interval. It is calculated as follows:

ME = Z*SE

where:

Z is the z-score corresponding to the desired confidence level

SE is the standard error

The z-score for a 95% confidence interval is 1.96. Therefore, the margin of error is:

ME = 1.96*0.026 = 0.051

Step 4: Calculate the confidence interval

The confidence interval is the interval of values that we are confident includes the true proportion of smokers who quit. It is calculated as follows:

CI = p +/- ME

In this case, the confidence interval is:

CI = 0.8 +/- 0.051 = (0.749, 0.851)

Therefore, the 95% confidence interval for the proportion of smokers who quit after 10 days of treatment is (0.749, 0.851).

User Cptstarling
by
2.7k points
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