4.3k views
4 votes
Please help out and explain the best you can! Tysm !

Please help out and explain the best you can! Tysm !-example-1
User Regene
by
8.9k points

1 Answer

4 votes

Answer:

Explanation:

From the graph attached,

Coordinates of the vertices of ΔOAB,

O → (0, 0)

A → (2, 4)

B → (5, 0)

If a point (h, k) is rotated 90° counterclockwise about the origin the image point will be,

(h, k) → (-k, h)

By this rule, if triangle OAB is rotated 90° counter clockwise, new vertices will follow the same rule,

O(0, 0) → O'(0, 0)

A(2, 4) → A'(-4, 2)

B(5, 0) → B'(0, 5)

By plotting these points we can get the image triangle.

Please help out and explain the best you can! Tysm !-example-1
User LionHeart
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories