Question

What is the final volume of a 3.5M NaOH solution if the original solution was 20mL of a 7.00M NaOH solution

Answer 1

0.04 L (or 40 mL)

Step-by-step explanation:

The dilution equation is:
`M_(s) V_(s) = M_(d) V_(d)`

`M_(s)` = the molarity of the sock solution

`V_(s)` = the volume of the sock solution

`M_(d)` = the molarity of the diluted solution

`V_(d)` = the volume of the diluted solution

We are given the original, or stock, solution, which is
`M_(s) = 7.00 M NaOH`, and
`V_(s) = 0.02 L (20 mL)`. We are also given the final molarity, which is:
`M_(d) = 3.5 M NaOH`.

So, plugging our given into the dilution equation, results in:

`7.00 M * 0.02 L = 3.5M * V_(d)` (divide both sides by 3.5 M, in order to get
`V_(d)` by itself).

`(7.00 M * 0.02 L)/(3.5M) = V_(d)`

`V_(d) = 0.04 L (or 40 mL)`

So, the final volume of a 3.5 M NaOH solution, with an original solution of 20 mL of a 7.00 M NaOH solution, is 0.04 L (or 40 mL)

Hopefully this helped. Good luck!