Question

What is the 12th term of the geometric sequence if a1= 30 and r=4.

Answer 1

a₁₂ = 30·4¹¹ = 15·2²³

Explanation:

`a_n=a_1\cdot r^(n-1)\\\\a_(12)=30\cdot 4^(12-1)\\\\a_(12)=30\cdot 4^(11)=15\cdot2\cdot2^(22)=15\cdot2^(23)`