Question

you have a gas that has a pressure of 2 atm and a volume of 10L. what would be the new volume if the pressure was changed to 1atm?​

Answer 1

20 Liters

Step-by-step explanation:

Boyles Law => ΔP ∝ 1/ΔT => P₁V₁ = P₂V₂ => V₂ = P₁V₁/P₂

P₁ = 2 atm

V₁ = 10 Liters

P₂ = 1 atm

V₂ = ?

V₂ = 2atm x 10L / 1atm = 20 Liters