Answer:
- The perimeter of ΔABC is 49 units.
Explanation:
We know that:
Work:
- => 2(ΔABC) = ΔXYZ
- => 2(11 + BC + CA) = (22 + 44 + 32)
- => (11 + BC + CA) = (22 + 44 + 32)/2
- => 11 + BC + CA = 11 + 22 + 16
- => Perimeter of ΔABC = 11 + 22 + 16
- => 49 units
Hence, the perimeter of ΔABC is 49 units.
Hoped this helped.