Question

Can some answer this math question

Answer 1

A

Explanation:

To multiply powers of a variable, add the exponents:

`x^m\cdot x^n = x^(m+n)`

This rule works for all exponents, positive, negative, or zero. Also, remember that
`x^0=1`.

Also, remember the definition of negative exponent:
`x^(-n) = (1)/(x^n)`

To multiply the two monomials, start by multiplying the coefficients, 14 and 4. That gives 56, so your answer begins with 56.

Now for the powers of x,
`(x^3)(x^(-5)) = x^(3+(-5)) =x^(-2) = (1)/(x^2)`

For the powers of y,
`(y^(-4))(y^4)=y^(4+(-4)) = y^0 = 1`
`(y^(-4))(y^4) = y^(-4+4) = y^0 =1`

Your answer is

`56 \cdot (1)/(x^2) \cdot 1 =(56)/(x^2)`