Question

What is the specific heat of a substance that absorbs 1600 joules of heat when a sample

of 18 g of the substance increases in temperature from 20 °C to 31°C? Round your answer
to two decimal places if necessary.

Answer 1

8.08 J/g °C

Step-by-step explanation:

Q=m*Cp*ΔT-->

Cp=Q/(m*ΔT) -->

Cp=1600/[18*(31-20)]-->

Cp=8.08 J/g °C